If Tom has three times as many testicles as Susan, and Susan has one-fourth as many ovaries as Joe, how many BBQ ribs does Mary have, if she has two more Ouija Boards than Tom?

30 thoughts on “Story Problem

  1. Easy. Sheesh.
    3.78³ Ribs over Πr² divided by ¾ Ouija Board.

    Of course, that is with the proviso that Tom, Susan, Joe and Mary all all transplanted Inuits, if not, then there is no way to tell and this is a trick question!

  2. Shoot, that makes more sense than most of them. Which probably explains why the math portion of my SAT indicates that I have the intelligence of an Ouija-less earthworm.

  3. Uncanny Mr Zilla, I was thinking of this equation just the other day…

    as in

    Bobby has 2 lemons, Jane has 6, the both left home at 6.45am, Bobby travelled in a easterly direction for 3 miles and Jane travelled westerly fo 15 miles.

    How many pizzas would it take for Bobby to meet Jane 5 miles from where he started if he was wearing an orange parka?

    damn home schooling

  4. Oh…yeah and the Higher Maths equivalent problem:

    If a woodchuck could chuck wood
    Then a woodchuch would chuck wood
    So how much wood would a woodchuck chuck
    If a woodchuck could chuck wood

  5. 😕 So Tom has no testies…Susan is only a quarter of the woman she used to be…and Joe is a she male? I’d have to say…

    (no testies X 1/4 of woman X a she male)divided by four quija boards = A whole lotta ribs! 😆

  6. So THATS the question! 42 indeed! Natalie & Rust made me spew my beverage, so Davezilla, you are doing your job!

  7. Easy, they all have zero gonads, and I’m not sure if there’s even one brain between them all. Oh, we weren’t counting brains, were we?

  8. Tom has more balls than Susan, but Joe is a bigger pussy than Susan. Mary has the most balls because she has more ouija boards than Tom, so she gets ALL the BBQ ribs. Mary killed Tom, Susan, and Joe and had herself six racks of ribs. Mary’s got balls of steel (which she used to knock each of the others out as she crept from behind them).

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